49x^2-110x-25=0

Solution for 49x^2-110x-25=0 equation:

49x^2-110x-25=0

a = 49; b = -110; c = -25;
Δ = b2-4ac
Δ = -1102-4·49·(-25)
Δ = 17000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17000}=\sqrt{100*170}=\sqrt{100}*\sqrt{170}=10\sqrt{170}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-10\sqrt{170}}{2*49}=\frac{110-10\sqrt{170}}{98}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+10\sqrt{170}}{2*49}=\frac{110+10\sqrt{170}}{98}
$